ini bagaimana caranya

Bab Program Linear
Matematika SMA Kelas XI

x = 2/3

4x + (5/2) y = 4 . (5/2)
4 (2/3) + (5y/2) = 10
5y/2 = 10 - 8/3
5y/2 = 30/3 - 8/3
y = 22/3 . 2/5
y = 44/15

titik potong = (2/3, 44/15)

pada gambar, terdapat 2 titik, yaitu (2/3, 44/15) dan (5/2, 0)
z = (2x - y)/3
z = (2 . 2/3 - 44/15)/3
z = (4/3 - 44/15)/3
z = (20 - 44)/(15 . 3)
z = -24/45
z = -8/15
karena nilai, maka hasilnya positif = 8/15

z = (2x - y)/3
z = (2 . 5/2 - 0)/3
z = 5/3

8/15 < 5/3

maka, jawabannya C