Diketahui y = x^2 / 2 - 3 / x^2. Hasil dari dy / dx=...

[tex] \frac{dy}{dx}( \frac{x^2}{2} - \frac{3}{x^2})\\ \frac{dy}{dx}( \frac{x^2}{2}) - \frac{dy}{dx}( \frac{3}{x^2})\\x - (\frac{-6}{x^3})\\x + \frac{6}{x^3} [/tex]

║MIPA Study Center ID║

[tex]\displaystyle y=\frac12x^2-\frac3{x^2}\\y=\frac12x^2-3x^{-2}\\\\y'=\frac12\cdot2x^{2-1}-3\cdot(-2)x^{-2-1}\\y'=1x^{1}+6x^{-3}\\\boxed{\boxed{y'=x+\frac6{x^{3}}}}[/tex]