kalo gini gimana ya? mohon bantuan

f(x) = 1/x
(fog)(x) = (x - 3) / 2x

(fog)(x) = f{g(x)}
(x - 3) / 2x = 1/g(x)
g(x) (x - 3) = 2x
g(x) = 2x / (x - 3)

y = 2x / (x - 3)
y (x - 3) = 2x
xy - 3y = 2x
xy - 2x = 3y
x (y - 2) = 3y
x = 3y / (y - 2)

g`¹(x) = 3x / (x - 2)

Opsi gak ada

Semoga berguna +_+

Fog(x) = (x - 3)/2x
f(g(x)) = (x - 3)/2x
1/g(x) = (x - 3)/2x
2x = g(x)(x - 3)
g(x) = 2x/(x - 3)
y = 2x/(x - 3)
y(x - 3) = 2x
xy - 3y = 2x
xy - 2x = 3y
x(y - 2) = 3y
x = 3y/(y - 2)
g¯¹(x) = (3x)/(x - 2)