Mohon bantuanyaaaaaaa

3^(2x² - 2x - 4) . 3^(x² + 3x - 10) > 3^(-4)
3^(3x² + x - 14) > 3^(-4)
3x² + x - 14 > -4
3x² + x - 10 > 0
(3x - 5)(x + 2) > 0
x < -2 aau x > 5/3

Opsi A.

[tex]\displaystyle 9^{x^2-x-2}\cdot3^{x^2+3x-10}\ \textgreater \ \frac1{81}\\3^{2x^2-2x-4+x^2+3x-10}\ \textgreater \ 3^{-4}\\3^{3x^2+x-14}\ \textgreater \ 3^{-4}\\\therefore\\3x^2+x-14\ \textgreater \ -4\\3x^2+x-10\ \textgreater \ 0\\3x^2+6x-5x-10\ \textgreater \ 0\\(3x-5)(x+2)\ \textgreater \ 0\\x\ \textless \ -2\vee x\ \textgreater \ \frac53\\\\\boxed{\boxed{\text{HP}=\left\{x|x\ \textless \ -2\vee x\ \textgreater \ \frac53,x\in\mathbb{R}\right\}}}[/tex]