tolong bantuannya ya kak... makasihh

[tex]\displaystyle K_p=\frac{(p\text{NH}_3)^2}{(p\text{N}_2)(p\text{H}_2)^3}\\9\cdot10^5=\frac{(p\text{NH}_3)^2}{(10)(1)^3}\\9\cdot10^6=(p\text{NH}_3)^2\\3\cdot10^3=p\text{NH}_3\\\\p=p\text{N}_2+p\text{H}_2+p\text{NH}_3\\p=10+1+3000\\\boxed{\boxed{p=3011\,\text{atm}}}[/tex]