Jika sin x = 3cos x, maka sin2x =... a. 1/6 b. 1/5 c. 3/5 d. 1/2 e. 3/10 + caranya ya

[tex]\displaystyle \sin x=3\cos x\\\tan x=3\\\frac{y}{x}=\frac31\\\\\therefore\\y=3\\x=1\\r=\sqrt{10}\\\\\sin2x=2\sin x\cos x\\\sin2x=\frac{2yx}{r^2}\\\sin2x=\frac{2\cdot3\cdot1}{(\sqrt{10})^2}\\\sin2x=\frac{6}{10}\\\boxed{\boxed{\sin2x=\frac35}}[/tex]