garis 2x+y-6=0 memotong garis x+2y-3=0 di titik A. tentukan persamaan garis yang melalui titik A dan tegak lurus garis y=3x-200

Cari titik A dgn metode SPLDV

2x + y - 6 = 0
--> 2x + y = 6

x + 2y - 3 = 0
--> x + 2y = 3... ×2
--> 2x + 4y = 6

2x + y =6
2x + 4y = 6
-------------------- -
-3y = 0
y = 0

2x + y = 6
2x + 0 = 6
x = 3

Titik A = (3,0)
y = 3x - 200
m = 3

tegak lurus
m1 x m2 = -1
3 x m2 = -1
m2 = -1/3 dan (3,0)

y - y1 = m(x - x1)
y - 0 = -1/3 ( x -3)
kali 3 kdua ruas
3y = - (x - 3)
3y = -x + 3
3y + x - 3 = 0

x + 3y - 3 = 0