Yang jago fisika pegas mohon bantuannya yaa!

[tex]\displaystyle \Delta x_1=0,1\,\text{cm}\\\Delta x_2=5\,\text{cm}\\W_1=2\,\text{J}\\\\F_2=?\\\\W_1=\frac12k\Delta x_1^2\\2=\frac12k\cdot0,1^2\\400\,\text{N/m}=k\\\\F_2=k\Delta x_2\\F_2=400\cdot0,05\\F_2=4\cdot5\\\boxed{\boxed{F_2=20\,\text{N}}}[/tex]

Elastisitas.
Kelas X kurikulum 2013 revisi 2016.

W = 1/2 kΔx₁²
k = 2W / Δx₁²

F = kΔx₂
   = 2W Δx₂ / Δx₁²
   = 2(2,0 J)(0,05 cm) / (0,1 cm)² = 20 N