3√8 pangkat x+2 = 1/32 pangkat 2-x maka nilai 8x-x pankat 2 adalah

[tex]\sqrt[3]{8^{x+2}} = ( \frac{1}{32})^{2-x}\\ \sqrt[3]{2^{3x+6}}=(2^{-5})^{2-x}\\2^{x+2} = 2^{5x-10}\\x + 2 = 5x - 10\\4x = 12\\\boxed{\boxed{\,\text{x = 3}}}\\\\\text{maka 8x - x}^2\,\,\text{adalah }\boxed{\boxed{\,\text{8(3) - 9 = 15}}}[/tex]

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