soal logaritma ^2 log x + ^2 log y^3 = 13 ^2 log x - ^2 log y = 5 nilai x+y adalah tolong pkai cara..

Bab Logaritma

2log x + 2log y^3 = 13
2log x + 3 × 2log y = 13
2log x = 13 - 3 × 2log y

2log x - 2log y = 5
2log x = 5 + 2log y

2log x = 2log x
13 - 3 × 2log y = 5 + 2log y
13 - 5 = 2log y + 3 × 2log y
8 = 4 × 2log y
2log y = 8/4
2log y = 2
y = 2^2
y = 4

2log x = 5 + 2log 4
2log x = 5 + 2
2log x = 7
x = 2^7
x = 128

x + y = 128 + 4 = 132

SPLDV
cara lain...
misal ²log x = a dan ²log y = b
dan x+ y = 2ᵃ + 2ᵇ

²log x  + 3 ²log y = 13 → a + 3b = 13
²log x  -  ²log y = 5 →  a - b = 5
kurangkan
4b = 8 --> b = 2
a- b = 5 --> a = 5 +b = 7

x+y = 2ᵃ + 2ᵇ = 2⁷+ 2² = 132