solve for x 2^(3-x) = 565

Bab Logaritma
Matematika SMA Kelas X

2^(3 - x) = 565
²log 565 = 3 - x
3 - x = log 565 / log 2
3 - x = 2,752 / 0,301
x = 3 - 9,14
x = -6,14

⇒log1023−x=log10 = 565
⇒(3−x)log10.2=2.7520
(3−x)(0.3010)=
2.7520

3−x=2.7520
0.3010=9.143
3.000−9.143=x
x=−6.143
.