Matematika

Pertanyaan

jika 2log a + 2log b = 12 dan 3 2log a - 2log b = 4. maka a+b

2 Jawaban

  • Misal x = 2log a dan y = 2log b
    2log a + 2log b = 12 ==> x + y = 12
    3 . 2log a - 2log b = 4 => 3x - y = 4
    -------------------------------------------------- +
    ................................................ 4x = 16 => x = 4
    x + y = 12 => 4 + y = 12 => y = 8
    x = 4
    => 2log a = 2log 2^4
    => a = 2^4 = 16

    y = 8
    => 2log b = 2log 2^8
    => b = 2^8 = 256

    a + b = 16 + 256 = 272
  • Bab Logaritma
    Matematika SMA Kelas X

    ²log a + ²log b = 12
    ²log ab = 12
    ab = 2¹²

    3 . ²log a - ²log b = 4
    ²log (a³ / b )_ = 4
    a³ / b = 2⁴
    b = a³/2⁴

    a . b = 2¹²
    a . a³/2⁴ = 2¹²
    a¹⁺³ = 2¹² ⁺ ⁴
    a⁴ = 2¹⁶
    a = 2^(16 : 4)
    a = 2⁴
    a = 16

    b = a³/2⁴
    b = 2³ˣ⁴ . 2⁻⁴
    b = 2¹² ⁻ ⁴
    b = 2⁸
    b = 256

    a + b = 16 + 256 = 272

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