Matematika

Pertanyaan

tolong bantuannya~
sekaligus cara kerjanya
tolong bantuannya~ sekaligus cara kerjanya

2 Jawaban

  • cos^3 x + 1/(cosec^3 x) = 0
    cos^3 x + sin^3 x = 0
    sin^3 x = - cos^3 x
    (sin^3 x)/(cos^3 x) = (- cos^3 x)/(cos^3 x)
    tan^3 x = -1
    tan x = -1
    tan x = Tan 135° = Tan 315°
    1) x = 135°
    Sin 2x = 2 sin x cos x = 2 sin 135° cos 135° = 2 . 1/2 √2 . -1/2 √2 = -1
    2) x = 315°
    Sin 2x = 2 sin x cos x = 2 sin 315° cos 315° = 2 . -1/2 √2 . 1/2 √2 = -1
  • cos^3 x + 1/(csc^3 x) = 0
    cos^3 x + sin^3 x = 0
    cos^3 x = -sin^3
    (cos^3x / -cos^3) = (-sin^3x)/(-cos^3)
    -1 = tan^3x
    tan x = -1 ( A )