tolonggg ga ketemu lagii:(

f(x) = (3x^2 - 10)/(x + 6) => f(0) = (3.0^2 - 10)/(0 + 6) = (-10)/6 = -5/3
f(x) = u/v
u = 3x^2 - 10 => u' = 6x
v = x + 6 => v' = 1
f'(x) = (u' v - v' u)/v^2
f'(x) = (6x (x + 6) - 1 (3x^2 - 10)) / (x + 6)^2
f'(0) = (6.0(0 + 6) - 1(3.0^2 - 10)) / (0 + 6)^2
f'(0) = (0(6) - 1(-10)) / 6^2
f'(0) = 10/36
f'(0) = 5/18

f(0) + 6 f'(0) = -5/3 + 6 (5/18) = -5/3 + 5/3 = 0

Matematika XI SMA
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Pembahasan :
f(x) = (3x² - 10)/(x + 6)
f(0) = (3.0² - 10)/(0 + 6) = -10/6 = -5/3

f'(x) = (3x² + 36x + 10)/(x + 6)²
f'(0) = (3.0² + 36.0 + 10)/(0 + 6)²
f'(0) = 10/36 = 5/18

Maka...
f(0) + 6f'(0)
= - 5/3 + 6(5/18)
= -5/3 + 5/3
= 0