Matematika

Pertanyaan

g(x) = [tex] \pi - 2x[/tex]
(fog)(x) = sin2x
f(x) = ......?

1 Jawaban

  • [tex]\displaystyle \pi-2x=a\\2x=\pi-a\\\\(f\circ g)(x)=\sin2x\\f(g(x))=\sin2x\\f(\pi-2x)=\sin2x\\f(a)=\sin(\pi-a)\\f(a)=\sin a\\\boxed{\boxed{f(x)=\sin x}}[/tex]

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