Suatu larutan berair mengandung 6,00% metanol (CH3OH) berdasar massa, dengan d=0,988 g/mL . berapa molaritas CH3OH dalam larutan ini?

[tex]\displaystyle \text{M}=\frac{n}{V}\\\text{M}=\frac{\frac{m}{\text{Mr}}}{V}\\\text{M}=\frac{\eta m}{V\text{Mr}}\\\text{M}=\frac{\eta\rho}{\text{Mr}}\\\text{M}=\frac{\frac{6}{100}\cdot988}{32}\\\text{M}=\frac{185,25}{100}\\\boxed{\boxed{\text{M}=1,8525\,\text{M}}}[/tex]