Tolong bantu nomor 5

a cos x + b sin x = k cos (x - ¢)
k = √(a^2 + b^2)
tan ¢ = b/a
f(x) = √3 cos x - sin x
a = √3, b = -1 => (a, b) = (√3, -1) => dikuadran 4

k = √((√3)^2 + (-1)^2) = √(3 + 1) = √4 = 2

tan ¢ = b/a = -1/√3 = -1/3 √3 = Tan 330°
¢ = 330° = 330°/180° π rad = 11/6 π rad