tolong bantu pake caranyaa yaa , urgent. makasih

1) f'(x) = 15x^2 - 4x - 5
f(x) = ∫ (15x^2 - 4x - 5) dx
f(x) = 15/3 x^3 - 4/2 x^2 - 5x + C
f(x) = 5x^3 - 2x^2 - 5x + C ==> f(2/5) = 0
f(2/5) = 5(2/5)^3 - 2(2/5)^2 - 5(2/5) + C = 0
=> 5 (8/125) - 2(4/25) - 2 + C = 0
=> 8/25 - 8/25 - 2 + C = 0
=> C = 2
f(x) = 5x^3 - 2x^2 - 5x + 2

2) dy/dx = 3x^2 - 6x + 1
y = ∫ (3x^2 - 6x + 1) dx
y = 3/3 x^3 - 6/2 x^2 + x + C
y = x^3 - 3x^2 + x + C ===> melalui (1, 2)
2 = 1^3 - 3(1)^2 + 1 + C
2 = 1 - 3 + 1 + C
2 = -1 + C
3 = C
y = x^3 - 3x^2 + x + 3