jika ³㏒a = 2 , maka (((a²)³)⁴)[tex] ^{\frac{1}{8} } } [/tex] X 1/81 A. 3 B. 9 C. 27 D. 81 E. 243

Bab Logaritma
Matematika SMA Kelas X

³log a = 2
a = 3²
a = 9

(((a²)³)⁴)^(1/8) . (1/81)
= (9)^(2 . 3 . 4 / 8) . (1/81)
= 9³ . 1/81
= 729 / 81
= 9

jawabannya B

[tex]\displaystyle ^3\log a=2\\a=3^2\\a=9\\\\\frac1{81}(((a^2)^3)^4)^\frac18=\frac1{81}\cdot9^{2\cdot3\cdot4\cdot\frac18}\\\frac1{81}(((a^2)^3)^4)^\frac18=\frac1{81}\cdot9^{3}\\\boxed{\boxed{\frac1{81}(((a^2)^3)^4)^\frac18=9}}[/tex]