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MOMENTUM

m = 300 gr = 0,3 kf
v = 36 km/j = 10 m/s
v' = -18 km/j = -5 m/s
∆p = __?

perubahan momentum
∆p = m ∆v
∆p = m (v' - v)
∆p = 0,3 • (-5 - 10)
∆p = - 4,5 kg m/s ← jwb

BESAR perubahan momentum 4,5 Ns