tolong pake cara ya plisss

[tex] \dfrac{^3 \log \sqrt{6}}{ (^3 \log 18)^2 - (^3 \log 2)^2} \\\\ Pada~penyebut \\ a^2 - b^2 = (a+b)(a-b) \\\\ \dfrac{ ^3 \log 6^{\frac{1}{2}}}{(^3 \log 18 + ^3 \log 2)(^3 \log 18 - ^3 \log 2)} \\\\ \dfrac{ \frac{1}{2} \times ^3 \log 6}{ (^3 \log (18 \times 2))(^3 \log (18 \div 2))} \\\\ \dfrac{ \frac{1}{2} \times ^3 \log 6}{ (^3 \log 36)(^3 \log 9)} \\\\ \dfrac{\frac{1}{2}\times ^3 \log 6}{^3 \log 6^2 \times 2} \\\\ \dfrac{ \frac{1}{2} \times ^3 \log 6}{ 2 \times ^3 \log 6 \times 2} \\\ Coret~ ^3 \log 6 \\\\ \dfrac{\frac{1}{2}}{4} \\\\ \dfrac{1}{8} [/tex]

Bab Logaritma
Matematika SMA Kelas IX

(³log √6) / ((³log 18)² - (³log 2)²)
= (³log √6) / ((³log 18 + ³log 2) (³log 18 - ³log 2))
= (³log √6) / ((³log (18 x 2) x ³log (18 : 2))
= (³log √6) / (³log 36 x ³log 9)
= (³log √6) / (2 x ³log 36)
= (³log (6^(1/2)) / (³log 36²)
= (1/2 . ³log 6) / (³log 1.296)
= 1/2 . ¹²⁹⁶log 6
= (1/2) . ^(6⁴)log 6
= (1/2) . (1/4) . ⁶log 6
= 1/8