Log41/35+log70-log41/2+2log5
Matematika
Nithinsamith
Pertanyaan
Log41/35+log70-log41/2+2log5
2 Jawaban
-
1. Jawaban ErikCatosLawijaya
Mapel : Matematika
Kelas : X SMA
Bab : Eksponen dan Logaritma
Pembahasan :
Log 41/35 + Log 70 - Log 41/2 + 2Log 5
= Log [41/35 . 70 / (41/2)] + Log 5²
= Log [82/(41/2)] + Log 25
= Log 4 + Log 25
= Log (4 x 25)
= Log 100
= 2 -
2. Jawaban Anonyme
Bab Logaritma
Matematika SMA Kelas X
log (41/35) + log 70 - log (41/2) + 2 . log 5
= log ((41/35) x 70 : (41/2) x 5²)
= log (41 x 2 x 25 x (2/41))
= log 100
= 2