Matematika

Pertanyaan

Log41/35+log70-log41/2+2log5

2 Jawaban

  • Mapel : Matematika
    Kelas : X SMA
    Bab : Eksponen dan Logaritma

    Pembahasan :
    Log 41/35 + Log 70 - Log 41/2 + 2Log 5
    = Log [41/35 . 70 / (41/2)] + Log 5²
    = Log [82/(41/2)] + Log 25
    = Log 4 + Log 25
    = Log (4 x 25)
    = Log 100
    = 2
  • Bab Logaritma
    Matematika SMA Kelas X

    log (41/35) + log 70 - log (41/2) + 2 . log 5
    = log ((41/35) x 70 : (41/2) x 5²)
    = log (41 x 2 x 25 x (2/41))
    = log 100
    = 2

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