Matematika

Pertanyaan

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bantuin pake cara ya makasihhh

1 Jawaban

  • [tex]\displaystyle \int\limits^{\ln2}_{1}\int\limits^{2}_{e^y}\,dxdy=\int\limits^{\ln2}_{1}x|^{2}_{e^y} dy\\\int\limits^{\ln2}_{1}\int\limits^{2}_{e^y}\,dxdy=\int\limits^{\ln2}_{1}2-e^y dy\\\int\limits^{\ln2}_{1}\int\limits^{2}_{e^y}\,dxdy=2y-e^y|^{\ln2}_{1}\\\int\limits^{\ln2}_{1}\int\limits^{2}_{e^y}\,dxdy=2\ln2-e^{\ln2}-2(1)+e^1\\\int\limits^{\ln2}_{1}\int\limits^{2}_{e^y}\,dxdy=2\ln2-2-2+e^1\\\boxed{\boxed{\int\limits^{\ln2}_{1}\int\limits^{2}_{e^y}\,dxdy=\ln4-4+e}}[/tex]