Jika a dan b memenuhi {2 per 2a-b + 7/2a+b = 3 { 1 per 2a-b - 7 per 2a + b = 0 Maka a2 + 2b = ?

[tex]\frac{2}{2a-b} + \frac{7}{2a+b} = 3 \\
\frac{1}{2a-b} - \frac{7}{2a+b} = 0 \\ \\

\frac{1}{2a-b} - \frac{7}{2a+b} = 0 \\
\frac{1}{2a-b} = \frac{7}{2a+b} \\
\frac{1}{2a-b} = \frac{7}{2a+b} \\ \\
\, substitusikan \\

\frac{2}{2a-b} + \frac{7}{2a+b} = 3 \\
\frac{2}{2a-b} + \frac{1}{2a-b} = 3 \\
\frac{3}{2a-b} = 3 \\
3 = 3(2a-b) \\
1 = 2a-b ----\ \textgreater \ (1) \\ \\

\frac{1}{2a-b} = \frac{7}{2a+b} \\
\frac{1}{1}= \frac{7}{2a+b} \\
(2a+b) = 7 \\
2a+b = 7 \\
2a+b = 7 ----\ \textgreater \ (2) \\ \\ [/tex]

[tex]2a-b=1 \\ 2a+b=7 \\ --------- (-) \\ -2b = -6\\ b = 3 \\ \\ 2a-b = 1 \\ 2a-(3) = 1 \\ 2a=4 \\ a =2[/tex]

Jika pertanyaannya [tex]a^{2} + 2b[/tex]
[tex](2)^{2} + 2(3) = 10[/tex]

Jika pertanyaannya [tex]2a+2b[/tex]
[tex]2a+2b = 2(2)+2(3) \\ 2a + 2b = 10[/tex]