Diferensial dr y = 1 / (x^3 + 2x )^2/3 Mohon dibantu gais

[tex]\displaystyle y=\frac{1}{(x^3+2x)^\frac23}\\y=(x^3+2x)^{-\frac23}\\\\\boxed{\boxed{y'=-\frac23\cdot(3x^2+2)(x^3+2x)^{-\frac53}}}[/tex]