Matematika

Pertanyaan

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2 Jawaban

  • 1) h(x) = (2x + 1)/(x - 1) + 2
    (2x + 1)/(x - 1) + 2 = y
    (2x + 1)/(x - 1) = y - 2
    (2x + 1) = (y - 2)(x - 1)
    2x + 1 = xy - y - 2x + 2
    2x + 2x - xy = -y + 2 - 1
    4x - xy = 1 - y
    x(4 - y) = (1 - y)
    x = (1 - y)/(4 - y) . (-1)/(-1)
    x = (y - 1)/(y - 4)
    h^-1(x) = (x - 1)/(x - 4) ; x ≠ 4

    15) f(x) = (2x - 3)/(4x + 1)
    (2x - 3)/(4x + 1) = y
    (2x - 3) = 4xy + y
    2x - 4xy = y + 3
    x(2 - 4y) = (y + 3)
    x = (y + 3)/(2 - 4y)
    f^-1(x) = (x + 3)/(2 - 4x) ; x ≠ 1/2
  • Materi : Invers Fungsi
    Tingkat : XI SMA

    Penyelesaian :
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    Jawaban :
    14. D
    15. B

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