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Matematika
royanamalik
Pertanyaan
Tolong pake cara juga ..
2 Jawaban
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1. Jawaban arsetpopeye
1) h(x) = (2x + 1)/(x - 1) + 2
(2x + 1)/(x - 1) + 2 = y
(2x + 1)/(x - 1) = y - 2
(2x + 1) = (y - 2)(x - 1)
2x + 1 = xy - y - 2x + 2
2x + 2x - xy = -y + 2 - 1
4x - xy = 1 - y
x(4 - y) = (1 - y)
x = (1 - y)/(4 - y) . (-1)/(-1)
x = (y - 1)/(y - 4)
h^-1(x) = (x - 1)/(x - 4) ; x ≠ 4
15) f(x) = (2x - 3)/(4x + 1)
(2x - 3)/(4x + 1) = y
(2x - 3) = 4xy + y
2x - 4xy = y + 3
x(2 - 4y) = (y + 3)
x = (y + 3)/(2 - 4y)
f^-1(x) = (x + 3)/(2 - 4x) ; x ≠ 1/2 -
2. Jawaban Jimbenaho
Materi : Invers Fungsi
Tingkat : XI SMA
Penyelesaian :
Silakan lihat di gambar
Jawaban :
14. D
15. B
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