sudut bad =47 a.nilai x ................

a.nilai x
x+39+x+x=180°
3x+39=180°
3x=180°-39°
3x=141°
x=141/3
x=47°

x = 180°- (∠CAB + ∠ABC)
= 180 - ([47+39] + 47)
= 180 - (86+47)
= 180 - 133
= 47°

atau singkatnya,,
x = ∠ACB = ∠BAD = ∠ABC = 47°