mohon bantuannya ya ????

1.[tex] \frac{81 a^{9} b^{2} }{3 a^{6} b^{5} } [/tex]
   =27a³b³=3³a³b³

2.10√3-5√3+8√3-7√3=(10-5+8-7)√3=6√3

3.[tex] \frac{( \sqrt{6} +5) ^{2} } {6-25} [/tex]=[tex]    \frac{6+25+10 \sqrt{3} }{-19} [/tex]

4.[tex] ^{5}log( 25x3/15)[/tex]=[tex] ^{5} log5=1[/tex]

5.[tex] ^{9} log150[/tex]=[tex] \frac{ ^{2}log150 }{ ^{2}log9 } [/tex]=[tex] \frac{2b+a+1}{2a} [/tex]

6.2 x ³log2 x ²log27 x 1/2=³log27=3

7-8 kepanjangan

good luck

no. 7
2x² - 3x - 14 = 0
(2x - 7)(x + 2) = 0
x1 = 7/2  x2 = -2 ( karena syarat x1 > x2)

2x1 + 3x2
= 2(7/2) + 3(-2)
= 7 - 6
= 1

no. 9
p + q = 3/2
p.q = 2

persamaan baru
α + β = (2p - 1) + (2q - 1)
         = 2p + 2q - 2
         = 2(p + q) - 2
         = 2(3/2) - 2
         = 3 - 2
         = 1

α.β = (2p - 1)(2q - 1)
      = 4pq - 2p - 2q + 1
      = 4(p.q) - 2(p + q) + 1
      = 4(2) - 2(3/2) + 1
      = 8 - 3 + 1
      = 6
persamaan baru
x² - (α + β)x + α.β = 0
x² - x + 6 = 0