Himpunan penyelesaian sistem pertidaksamaan { 5/x + 4/y =13, 3/x - 2/y =21 adalah {(x0,y0)}, maka nilai x0 - y0 adalah...

Mapel : Matematika
Kelas : VIII SMP
Bab : SPLDV

Pembahasan :
Terlampir...

X0 - Y0
= 1/5 - (-1/3)
= 1/5 + 1/3
= (3 + 5)/5.3
= 8/15

5/x + 4/y = 13
3/x - 2/y = 21

misal :
p = 1/x
q = 1/y

5p + 4q = 13 (× 1)
3p - 2q = 21 (× 2)

5p + 4q = 13
6p - 4q = 42
------------------- +
11p = 55
p = 55/11
p = 5

5p + 4q = 13
5(5) + 4q = 13
25 + 4q = 13
4q = 13 - 25
4q = - 12
q = - 12/4
q = - 3

p = 1/x
5 = 1/x
x = 1/5

q = 1/y
- 3 = 1/y
y = - 1/3

Hp = {(1/5 , - 1/3)}

nilai x0 - y0 = 1/5 - (- 1/3)
nilai x0 - y0 = 1/5 + 1/3
nilai x0 - y0 = 3/15 + 5/15
nilai x0 - y0 = 8/15

Jadi nilai x0 - y0 adalah 8/15