jika diketahui f(x)=20x^7/2+2x^5/2+10x,maka f'(4) adalah....

f(x) = 20x^7/2 + 2x^5/2 + 10x

Turunan
f'(x) = 20(7/2)x^(7/2 - 1) + 2(5/2)x^(5/2 - 1) + 10
f'(x) = 70x^5/2 + 5x^3/2 + 10

f'(4) = 70(4)^5/2 + 5(4)^3/2 + 10
f'(4) = 70(2²)^5/2 + 5(2²)^3/2 + 10
f'(4) = 70(2^5) + 5(2³) + 10
f'(4) = 2.240 + 40 + 10
f'(4) = 2.290

Semoga berguna +_+