Mohon bantuanyaaaaaaa

ingat bahwa x1*x2 =c/a
Semoga bermanfaat :)

[tex]\displaystyle 3^{6x-2y}=\frac1{81}\\3^{6x-2y}=3^{-4}\\\therefore\\6x-2y=-4\\6x+4=2y\\\\-2x^2+2y=5\\-2x^2+6x+4=5\\-2x^2+6x-1=0\\\\x_1x_2=\frac ca\\x_1x_2=\frac{-1}{-2}\\\boxed{\boxed{x_1x_2=\frac12}}[/tex]