Bantu ya bwanggggggg

[tex]\displaystyle \sin\angle\text{PQR}=\frac{\text{RT}}{\text{RQ}}\\\sin60^\circ=\frac{\text{RT}}{p}\\\frac12p\sqrt3=\text{RT}\\\\\text{PR}^2=\text{PT}^2+\text{RT}^2\\\text{PR}^2=\left(\frac32p\right)^2+\left(\frac12p\sqrt3\right)^2\\\text{PR}^2=\frac94p^2+\frac34p^2\\\text{PR}^2=\frac{12}4p^2\\\text{PR}^2=3p^2\\\boxed{\boxed{\text{PR}^2=p\sqrt3}}[/tex]