Gunakan aturan untuk mencari turunan A) Y=6Xkuadrat -xpangkat3+5xpangkat-2 B) ykuadrat =1-2xkuadrat/x+1
Matematika
oginugraha97
Pertanyaan
Gunakan aturan untuk mencari turunan
A) Y=6Xkuadrat -xpangkat3+5xpangkat-2
B) ykuadrat =1-2xkuadrat/x+1
A) Y=6Xkuadrat -xpangkat3+5xpangkat-2
B) ykuadrat =1-2xkuadrat/x+1
1 Jawaban
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1. Jawaban Anonyme
[tex]\displaystyle y=6x^2-x^3+5x^{-2}\\\\y'=6\cdot2x^{2-1}-1\cdot3x^{3-1}+5\cdot(-2)x^{-2-1}\\y'=12x^{1}-3x^{2}-10x^{-3}\\\boxed{\boxed{y'=12x-3x^{2}-\frac{10}{x^{3}}}}[/tex]
[tex]\displaystyle y^2=\frac{1-2x^2}{x+1}\\y=\sqrt{\frac{1-2x^2}{x+1}}\\y=((1-2x^2)(x+1)^{-1})^\frac12\\y=(1-2x^2)^\frac12(x+1)^{-\frac12}\\\\y'=\frac12(-4x)(1-2x^2)^{-\frac12}(x+1)^{-\frac12}-\frac12(1)(1-2x^2)^\frac12(x+1)^{-\frac32}\\y'=-2x(1-2x^2)^{-\frac12}(x+1)^{-\frac12}-\frac12(1-2x^2)^\frac12(x+1)^{-\frac32}\\y'=-\frac{2x}{(1-2x^2)^{\frac12}(x+1)^{\frac12}}-\frac{(1-2x^2)^\frac12}{2(x+1)^{\frac32}}[/tex]
[tex]\displaystyle y'=-\frac{2x}{\sqrt{(1-2x^2)(x+1)}}-\frac{1}{2x+2}\sqrt{\frac{1-2x^2}{x+1}}[/tex]