air asin tertentu mempunyai 3,87% NaCI berdasarkan massa. sebanyak 75,0 mL sampel bobotnya 76,9 gram. berapa liter larutan ini harus di uapkan sampai kering unt

m sampel = 76,9 gram
% NaCl = 3,87%
m NaCl = 3,87% × 76,9 gram = 2,97603 gram

mj sampel = m / V
= 76,9 gr / 75 mL
= 1,02533 gr/mL
= 1025,33 kg/L

V sampel = 75 mL

m NaCl` = 725 kg
m sampel` = (100% / 3,87%) × 735 kg = 18733,85 kg

V sampel` = ... ?

V sampel` = m sampel` / mj sampel
= 18733,85 kg / 1025,33 kg/L
= 18,523 L

*mj = massa jenis

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