Matematika

Pertanyaan

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2 Jawaban

  • [tex] \frac{1}{2}- \frac{2}{3}x= \frac{1}{4}-x [/tex]
    [tex]- \frac{2}{3}x+x= \frac{1}{4}- \frac{1}{2} [/tex]
    [tex] \frac{1}{3}x=- \frac{1}{4} [/tex]
    [tex]x=- \frac{1}{4} [/tex] ÷ [tex] \frac{1}{3} [/tex]
    [tex]x=- \frac{1}{4} [/tex] × 3
    [tex]x=- \frac{3}{4} [/tex]

    [tex] \frac{x}{3}= \frac{- \frac{3}{4}}{3}= -\frac{3}{4} . \frac{1}{3}= -\frac{1}{4} [/tex]
    (D)
  • 1/2 - 2/3x = 1/4 - x
    -2/3x + x = 1/4 - 1/2
    1/3 x = -1/4
    4x = -3
    x = -3/4

    Maka...
    x/3
    = (-3/4)/3
    = -3/12
    = - 1/4