nanya lagi dong gaes

6log98 = (²log98)/(²log6)
= (²log7.7.2)/(²log3.2)
= (²log7 + ²log7 + ²log2) / (²log3 + ²log2)
= (1/a + 1/a + 1) / (b + 1)
= (2/a + 1) / (b + 1) . a/a
= (2 + a) / (a(b + 1)
= (a + 2) / a(1 + b)

⁶log 98
= Log 98 / Log 6
= ²log 98 / ²log 6
= ²log (7² . 2) / ²log (3 . 2)
= [²log 7² + ²log 2] / [²log 3 + ²log2]
= [2.1/a + 1]/[b + 1]
= (2/a + 1)/(b + 1)
= (2 + a)/(ab + a)
= (2 + a)/[a(b + 1)]