Mohon dibantu yaaahhh
SBMPTN
afnims
Pertanyaan
Mohon dibantu yaaahhh
1 Jawaban
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1. Jawaban arsetpopeye
Tan x positif di kuadran 1 (x) dan kuadran 3 (180° + x)
Tan x = Tan (180° + x)
Lim (x + π/2) (1 - sin x) / tan 2x
x=>-π/2
Lim (x + π/2) (1 - sin x) / tan (π + 2x)
x=>-π/2
Lim (1 - sin x) (x + π/2)/(tan 2(x + π/2))
x=>-π/2
= (1 - sin (-π/2)) . 1/2
= (1 - (-1)) . 1/2
= 2 . 1/2
= 1