diketahui f(x2+x+2) = x2-x-2 dengan x lebih besar sama dengan 0 maka f(4) = a.12 b.10 c.2 d.-8 e.-12

x² + x + 2 = 4
x² + x - 2 = 0
(x + 2)(x - 1) = 0
↑↑ Tidak memenuhi

x = 1
f(x² + x + 2) = x² - x - 2
f(4) = 1² - 1 - 2
f(4) = -2

[tex]\displaystyle x^2+x+2=4\\x^2+x-2=0\\(x+2)(x-1)=0\\x=-2\vee x=1\\\\f(x^2+x+2)=x^2-x-2\\f(4)=1^2-1-2\\f(4)=1-1-2\\\boxed{\boxed{f(4)=-2}}[/tex]