berserta caranya.. makasihh

jawabannya insaallah c

AB = (2 ... 3)(2 ... 0) = (4 + 3 ... 0 + 9) = (7 ... 9)
......... (1 ... 0) (1 ... 3) ... (2 + 0 ... 0 + 0) .. (2 ... 0)

AB + C = (7 ... 9) + (-5 ... -6) = (2 ... 3)
................. (2 .. 0) .. (2 .... 8) .... (4 ... 8)

Determinan (AB + C) = 2(8) - 4(3) = 16 - 12 = 4