tolong di jawab ya nomor 8

[tex]\displaystyle \text{Luas segitiga apabila diketahui koordinatnya}\\\\L=\frac12\left|\begin{array}{ccc}x_1&y_1\\x_2&y_2\\x_3&y_3\\x_1&y_1\end{array}\right|\\L=\frac12\left|\begin{array}{ccc}5&2\\-4&6\\1&-3\\5&2\end{array}\right|\\L=\frac12(5\cdot6+(-4)\cdot(-3)+1\cdot2-2\cdot(-4)-1\cdot6-(-3)\cdot5)\\L=\frac12(30+12+2+8-6+15)\\L=\frac12(61)\,\text{sL}\\\\\text{Luas bayangan }\Delta\text{ABC}\\L'=\left|\begin{array}{ccc}2&0\\0&1\end{array}\right|L\\L'=(2\cdot1-0\cdot0)\cdot\frac12(61)[/tex]
[tex]\displaystyle L'=(2)\cdot\frac12(61)\\\boxed{\boxed{L'=61\,\text{sL}}}[/tex]