sebuah kerucut memiliki tinggi 30cm dan keliling alasnya 66cm.jika diket.π=22/7,volume kerucut tsb adl....

r = 66 x 7/22 / 2 = 10,5 cm
V = 1/3 x 22/7 x 30 x 10,5 x 10,5 = 3465 cm3

D1:t=30cm kell.alas kerucut:66cm phi=22/7 D2: V kerucut D3:V kerucut=1/3×phi×r2×t Kell alas=keliling lingkaran 66cm=2 ×phi×r 66cm=2×22/7×r 66cm=44/7×r 66÷44/7 =66×7/44 33×7/22 231/22=10.5 # r= 10.5 cm V.kerucut=1/3×phi×r2×t= 1/3×22/7×10.5×10.5×30= 1/3×22×1.5.10.5.30= 1/3×33×10.5×30= 1/3×33×315= 11×315=3465 cm3