jika A,B memenuhi sistem2a/a-2b dikurang 6b/a+2b=3 dan -a/a-2b ditambah 6b/a+2b =-1 Maka ab/a pangkat dua- 4b pangkat dua =....

(2a/a-2b)-(6b/a+2b)=3
(-a/a-2b)+(6b/a+2b)=-1
a/a-2b = 2
a = 2a-4b
4b = a
(2(4b)/4b-2b)-(6b/4b+2b)=3
8b/2b - 6b/6b = 3
4b-1=3
b = 1
a = 4

(ab/a)^2 - (4b)^2 = (4/4)^2 - (4)^2 = 1-16 = -15