Tolong di jawab. Aku ga paham beginian :(

Matematika X SMA
→→ Logaritma ←←

Pembahasan :
⁴log 6 = m
⁴log (3.2) = m
⁴log 3 + ⁴log 2 = m
⁴log 3 = m - ⁴log 2
⁴log 3 = m - 1/2
⁴log 3 = (2m - 1)/2

12'log 60
= ⁴log 60 / ⁴log 12
= ⁴log (6. 10) / ⁴log (4 . 3)
= [⁴log 6 + ⁴log 10]/[⁴log 4 + ⁴log 3]
= [m + 1/n]/[1 + (2m - 1)/2]
= [(mn + 1)/n]/[(2m + 1)/2]
= (2mn + 2)/(2mn + n)