Jika f(x)=1/x+2 dan (fog) (x) =1/x^2+3 maka g(x-1)=....

[tex]\text{f(x) = } \frac{1}{x + 2}\\\\\text{fog(x) = f(g(x))}\\ \frac{1}{x^2 + 3}= \frac{1}{g(x) + 2}\\g(x) + 2 = x^2 + 3\\g(x) = x^2 + 1\\g(x - 1) = (x - 1)^2 + 1\\g(x - 1) = x^2 - 2x + 2 [/tex]

║MIPA Study Center ID║

f(x) = 1/x+2
(f○g)(x) = 1/x^2+3
f(g(x)) = 1/x^2+3
1/g(x)+2 = 1/x^2+3
g(x) = x^2+3-2
g(x) = x^2+1
g(x-1) = (x-1)^2+1
g(x-1) = x^2-2x+1+1
g(x-1) = x^2-2x+2

Jadi g(x-1) = x^2 - 2x + 2