pliiiiissssss yang bisa mohon dijawab no 35. beserta caranya

PERSEGI ABCD
AB = BC = CD = DA = 12 cm
CG : GB = 1 : 2
CF = 2 cm
L segilima AEGCD = ...??

CG : GB = 1 : 2

CG = 1/(1+2) × 12
CG = 1/3 × 12
CG = 12/3
CG = 4 cm

GB = 2/(1+2) × 12
GB = 2/3 × 12
GB = 24/3
GB = 8 cm

CG/GB = CF/BE
4/8 = 2/BE
BE = (2×8)/4
BE = 16/4
BE = 4 cm

L segilima AEGCD = L persegi ABCD - L segitiga BEG
L segilima AEGCD = AB^2 - (1/2 × BE × GB)
L segilima AEGCD = 12^2 - (1/2 × 4 × 8)
L segilima AEGCD = (12 × 12) - (1/2 × 4 × 8)
L segilima AEGCD = 144 - 16
L segilima AEGCD = 128 cm^2

Jadi luas segilima AEGCD adalah 128 cm^2 (C)

CG = BE

perbandingan =
CG = 1
GB = 2
seluruh perbandingan = 1+2 = 3

CG = 1/3 × 12 = 4cm
GB = 2/3 × 12 = 8cm

luas segilima =
(S×S) - (a × t × 1/2) =
(12×12) - ( 4 × 8 × 1/2 ) =
144 - 16 =
128cm^2 { C }

#semoga membantu....