tolong dibantu ya nomer tiga

f(1) = 2
f(2) = f(1+1) = f(1x1) = f(1) = 2
f(3) = f(2+1) = f(2x1) = f(2) = 2
f(4) = f(3+1) = f(3x1) = f(3) = 2
dst mk
f(2014) = 2

[tex]\displaystyle f(2)=f(1+1)\\f(2)=f(1\cdot1)\\f(2)=f(1)\\f(2)=2\\\\f(3)=f(2+1)\\f(3)=f(2\cdot1)\\f(3)=f(2)\\f(3)=2\\\\f(4)=f(3+1)\\f(4)=f(3\cdot1)\\f(4)=f(3)\\f(4)=2\\\\\vdots\\\\f(2014)=f(2013+1)\\f(2014)=f(2013\cdot1)\\f(2014)=f(2013)\\\boxed{\boxed{f(2014)=2}}[/tex]