bantu aku yaa:v.......

<AOC + <BOC = 180
6x - 5 + (2x + 25) = 180
8x + 20 = 180
8x = 160
x = 20

↓
Maka,
<BOC = 2(20) + 25
<BOC = 65°

Jawaban B

- sudut berpelurus

∠AOC= (6x - 5)°
∠BOC= (2x + 25)°
jumlahnya= 180°

maka,
∠AOC + ∠BOC= 180
(6x - 5) + (2x + 25)= 180
6x + 2x - 5 + 25= 180
8x + 20= 180
8x= 180 - 20
8x= 160
  x= 20

besar ∠BOC
∠BOC= (2x + 25)°
∠BOC= (2(20) + 25)°
∠BOC= (40 + 25)°
∠BOC= 65° → jawaban b