Jika 4log 6 = m + 1, maka 9log 8 = ..... a 3/(4m + 2 ) b 3/(4m - 2 ) c 3/(2m +4 ) d 3/(2m - 4 ) e 3/(4m + 4 )

^4 log 6 = m + 1
1/2 ² log (2 x 3 = m + 1
² log 2 + ² log 3 = 2(m + 1)
1 + ² log 3 = 2m + 2
² log 3 = 2m + 2 - 1
² log 3 = 2m + 1

^9 log 8
^3² log 2³
= 3/2 ³ log 2
= (3/2) (1/² log 3)
= (3/2(2m + 1)
= 3/(4m + 2)