Matematika

Pertanyaan

Bantu jawab donk, ane gak tau
Bantu jawab donk, ane gak tau

1 Jawaban

  • g(x) = (x + 1)^2
    (g o f)(x) = (log x)^2 + 2 (log x) + 1
    g(f(x)) = (log x)^2 + 2 (log x) + 1
    (f(x) + 1)^2 = ((log x) + 1)^2
    f(x) + 1 = ± ((log x) + 1)

    1) f(x) + 1 = (log x) + 1
    f(x) = (log x)
    f(0,001) = (log 0,001) = log 10^-3 = -3 log 10 = -3 (1) = -3 (tak ada di option)

    2) f(x) + 1 = - ((log x) + 1)
    f(x) = - ((log x) + 1) - 1
    f(0,001) = - ((log 0,001) + 1) - 1
    = - ((log 10^-3) + 1) - 1
    = - (-3 (log 10) + 1) - 1
    = - (-3(1) + 1) - 1
    = - (-2) - 1
    = 2 - 1
    = 1 (ada di option yaitu B)

    2) f(x) = px - 3
    g(x) = (p + 1)x - 2 = px + x - 2

    (f o g)(x) = f(g(x))
    = f(px + x - 2)
    = p(px + x - 2) - 3
    = p^2 x + px - 2p - 3

    (g o f)(x) = g(f(x))
    = g(px - 3)
    = p(px - 3) + (px - 3) - 2
    = p^2 x - 3p + px - 5

    (f o g)(x) - 3 = (g o f)(x) + 1
    (p^2 x + px - 2p - 3) - 3 = (p^2 x - 3p + px - 5) + 1
    -2p - 3 - 3 = -3p - 5 + 1
    -2p - 6 = -3p - 4
    -2p + 3p = -4 + 6
    p = 2

    2p = 2(2) = 4