Bantu jawab donk, ane gak tau
Matematika
akbarchopper
Pertanyaan
Bantu jawab donk, ane gak tau
1 Jawaban
-
1. Jawaban arsetpopeye
g(x) = (x + 1)^2
(g o f)(x) = (log x)^2 + 2 (log x) + 1
g(f(x)) = (log x)^2 + 2 (log x) + 1
(f(x) + 1)^2 = ((log x) + 1)^2
f(x) + 1 = ± ((log x) + 1)
1) f(x) + 1 = (log x) + 1
f(x) = (log x)
f(0,001) = (log 0,001) = log 10^-3 = -3 log 10 = -3 (1) = -3 (tak ada di option)
2) f(x) + 1 = - ((log x) + 1)
f(x) = - ((log x) + 1) - 1
f(0,001) = - ((log 0,001) + 1) - 1
= - ((log 10^-3) + 1) - 1
= - (-3 (log 10) + 1) - 1
= - (-3(1) + 1) - 1
= - (-2) - 1
= 2 - 1
= 1 (ada di option yaitu B)
2) f(x) = px - 3
g(x) = (p + 1)x - 2 = px + x - 2
(f o g)(x) = f(g(x))
= f(px + x - 2)
= p(px + x - 2) - 3
= p^2 x + px - 2p - 3
(g o f)(x) = g(f(x))
= g(px - 3)
= p(px - 3) + (px - 3) - 2
= p^2 x - 3p + px - 5
(f o g)(x) - 3 = (g o f)(x) + 1
(p^2 x + px - 2p - 3) - 3 = (p^2 x - 3p + px - 5) + 1
-2p - 3 - 3 = -3p - 5 + 1
-2p - 6 = -3p - 4
-2p + 3p = -4 + 6
p = 2
2p = 2(2) = 4