Matematika

Pertanyaan

tolong bantuannya~
sekaligus cara kerjanya
tolong bantuannya~ sekaligus cara kerjanya

2 Jawaban

  • OA = a = (t^2 + 1, t)
    OB = b = (1, 2) => |b| = √(1^2 + 2^2) = √(1 + 4) = √5

    OA.OB = (t^2 + 1)(1) + t(2) = t^2 + 2t + 1

    Panjang proyeksi OA terhadap OB < 9/√5
    (OA.OB) / |OB| < 9/√5
    (t^2 + 2t + 1)/√5 < 9/√5
    t^2 + 2t + 1 < 9
    t^2 + 2t - 8 < 0
    (t + 4)(t - 2) < 0
    t = -4 atau t = 2
    Garis bilangan
    +++ (-4) --- (2) +++
    -4 < t < 2

  • |OB| = √(1^2 + 2^2) = √(1 + 4) = √5

    OA.OB = (t^2 + 1)(1) + t(2) = t^2 + 2t + 1

    Panjang proyeksi OA terhadap OB < 9/√5
    (OA.OB) / |OB| ≤ 9/√5
    (t^2 + 1 ,t) (1,2) /√5 ≤ 9/√5
    (t^2 + 1)(1) + t(2) /√5 ≤ 9/√5
    [√5 dicoret]

    t^2 + 2t + 1 ≤ 9
    t^2 + 2t + 1 - 9 ≤ 0
    t^2 + 2t - 8 ≤ 0
    (t + 4)(t - 2) ≤ 0
    t = -4 ≤ 0 atau
    0 ≤ t = 2

    -4 ≤ t ≤ 2 ( E )